Work Energy and Power Class 11 Physics Notes for IIT JEE | NEET

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Work Energy and Power Class 11 Physics Notes

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Chapter Overview & Exam Weightage 

Work, Energy and Power is Chapter 6 of NCERT Class 11 Physics. It is one of the mega chapters of mechanics — concepts from this chapter appear not only in their own right but as tools inside problems on rotational motion, centre of mass, fluid mechanics, and even thermodynamics.

The chapter introduces the energy method of solving mechanics problems. Instead of resolving forces and applying Newton's second law (which requires knowing acceleration at every instant), the energy method uses initial and final states only — making it vastly more powerful for complex problems.

Exam Weightage

Exam

Questions Per Year (approx.)

Marks

Most Tested Topics

JEE Main

2–3

8–12

Work-energy theorem, spring PE, power, collisions

JEE Advanced

1–2

4–8

Variable force work, energy conservation in complex systems

NEET

2–3

8–12

KE-PE interconversion, conservative forces, work formula

CBSE Class 11 Board

3–5

10–15

All NCERT definitions, derivations, solved examples

💡 Expert Tip by Saransh Gupta, IIT Bombay AIR-41: "Work-Energy and Power is what I call a 'force multiplier' chapter. Students who master energy methods here solve NLM problems faster, rotational problems without torque calculations, and fluid problems without pressure integration. The effort invested here multiplies across the entire mechanics syllabus."

Work, Energy, and Power Class 11 Physics Notes 

India's Best Exam Preparation for Class 11th - Download Now

work energy and power class 11 notes

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

India's Best Exam Preparation for Class 11th - Download Now

Work — Definition, Formula & Special Cases 

Definition

Work is done by a force on an object when the force causes displacement of the object. Work is a scalar quantity.

Formula

For a constant force F acting on an object that undergoes a displacement s, the work done is:

W = F·s = Fs cosθ

where θ is the angle between the force vector and the displacement vector.

  • W = Fs when F ∥ s (θ = 0°) → maximum positive work
  • W = 0 when F ⊥ s (θ = 90°) → no work done (e.g., centripetal force, normal force on horizontal surface)
  • W = –Fs when F anti-parallel to s (θ = 180°) → maximum negative work (e.g., friction opposing motion)

SI unit of work: Joule (J) = N·m = kg·m²/s²

Work Done by Variable Force

When force varies with position, work is calculated by integration:

W = ∫F·ds (from initial to final position)

Graphically: work = area under the F–x graph (F vs. displacement graph).

Special Cases of Work

Situation

Work Done

Reason

Carrying a bag horizontally (weight acts down, motion horizontal)

W = 0

F ⊥ displacement

Pushing against a wall (no movement)

W = 0

Displacement = 0

Friction on a sliding object

W = –fs (negative)

Force opposite to displacement

Gravity on a falling object

W = +mgh (positive)

Force and displacement both downward

Gravity on a rising object

W = –mgh (negative)

Force downward, displacement upward

Spring force compressing the spring by x

W = –½kx²

Spring force opposes compression

Conservative vs Non-Conservative Forces

Property

Conservative Force

Non-Conservative Force

Work done depends on?

Only start and end points

Path taken

Work in a closed loop

Zero

Non-zero

Associated PE

Yes

No

Examples

Gravity, spring force, electrostatic force

Friction, air resistance, viscosity


Work-Energy Theorem 

Statement

The net work done on an object by all forces acting on it equals the change in its kinetic energy:

W_net = ΔKE = KE_final – KE_initial = ½mv² – ½mu²

Derivation (from Newton's Second Law)

From Newton's 2nd law: F = ma

Using kinematics: v² = u² + 2as → as = (v² – u²)/2

Therefore: W = F·s = ma·s = m·(v² – u²)/2 = ½mv² – ½mu² = ΔKE ✓

Key Applications of the Work-Energy Theorem

  1. Finding velocity after a force acts over a known displacement — without needing time
  2. Finding displacement when the initial and final speeds are known, and the force is known
  3. Finding the force required to change an object's speed over a given distance
  4. Problems where multiple forces act — sum all work done and equate to ΔKE

Work-Energy Theorem with Friction

When friction acts:

W_net = W_applied + W_friction + W_gravity = ΔKE

W_friction = –f × d (always negative — friction removes energy from the system)

💡 Expert Tip by Saransh Gupta, IIT Bombay AIR-41: "In JEE problems, whenever you see a question asking for speed at a certain point after a force has acted — reach for the work-energy theorem first. It avoids the need to know acceleration at every instant, which is often impossible in problems with variable forces or multiple simultaneous forces."


Kinetic Energy

Definition

Kinetic energy is the energy possessed by an object due to its motion.

KE = ½mv²

where m = mass, v = speed. KE is always non-negative.

Key Relations

Relation

Formula

Use

KE in terms of momentum p

KE = p²/(2m)

When momentum is given, not velocity

Momentum in terms of KE

p = √(2m·KE)

Convert between KE and momentum

Ratio of KE of same momentum

KE ∝ 1/m

A lighter body has more KE for same p

Ratio of momentum at same KE

p ∝ √m

Heavier body has more momentum for same KE

KE and Momentum — Important Comparisons (JEE/NEET Favourite)

If two bodies A and B have the same kinetic energy:

  • p_A/p_B = √(m_A/m_B) → heavier body has larger momentum

If two bodies A and B have the same momentum:

  • KE_A/KE_B = m_B/m_A → lighter body has larger kinetic energy

Potential Energy — Gravitational & Spring 

Potential energy is the energy stored in an object due to its position or configuration in a force field. It is associated only with conservative forces.

Gravitational Potential Energy

PE_gravity = mgh

where h is the height above the chosen reference level (usually ground).

  • Reference level is chosen by the problem — PE can be negative if the object is below reference level
  • Only the change in PE matters, not the absolute value
  • ΔPE_gravity = mg(h₂ – h₁)

Spring Potential Energy (Elastic Potential Energy)

For a spring with spring constant k, compressed or stretched by x from its natural length:

PE_spring = ½kx²

  • Always positive (stored energy, whether compressed or stretched)
  • Maximum at maximum compression/extension
  • Zero at natural length

Relation Between Conservative Force and Potential Energy

F = –dU/dx (in one dimension)

The conservative force is the negative derivative of potential energy with respect to position. This is analogous to E = –dV/dx in electrostatics.

Equilibrium from Potential Energy

Condition

dU/dx

d²U/dx²

Type of Equilibrium

Stable

0

> 0 (minimum U)

Returns to equilibrium when displaced

Unstable

0

< 0 (maximum U)

Moves away when displaced

Neutral

0

0 (constant U)

Stays in new position


Conservation of Mechanical Energy 

Statement

In the absence of non-conservative forces (friction, air resistance), the total mechanical energy of a system remains constant:

KE + PE = constant

½mv₁² + U₁ = ½mv₂² + U₂

When Energy is NOT Conserved

If non-conservative forces (friction, viscosity) act:

W_friction = ΔKE + ΔPE = ΔE_mechanical

The work done by friction equals the loss in mechanical energy of the system. This energy is converted to heat.

Standard Applications

Problem

Energy Conservation Equation

Ball dropped from height h

mgh = ½mv² → v = √(2gh)

Block sliding down frictionless incline

mgh = ½mv² (same result)

Spring-mass system at maximum compression

½mv² = ½kx² → x = v√(m/k)

Pendulum — max height from lowest point

mgh = ½mv₀² → h = v₀²/(2g)

Block on spring (friction present)

½mv² = ½kx² + f·x (friction does negative work)


Power 

Definition

Power is the rate of doing work — the work done per unit time.

P = W/t = F·v cosθ

For maximum power (F parallel to v): P = Fv

SI unit of power: Watt (W) = J/s = kg·m²/s³

Other units: 1 horsepower (hp) = 746 W; 1 kW = 1000 W

Instantaneous vs Average Power

Type

Formula

When to Use

Average power

P_avg = W_total/t_total

Constant or varying force over time interval

Instantaneous power

P_inst = F·v = Fv cosθ

At a specific instant

Important Power Formulas

Situation

Formula

Constant force, constant velocity

P = Fv

Pump lifting water

P = ρVgh/t = ρAhvg (where v = h/t)

Engine at terminal velocity (F_engine = F_friction)

P_engine = F_friction × v

Electric power

P = VI = I²R = V²/R

Efficiency

η = (Useful power output / Total power input) × 100%

η = (Useful work output / Total work input) × 100%


Collisions — Elastic & Inelastic 

Collisions are governed by conservation of momentum (always) and conservation of kinetic energy (only for elastic collisions).

Types of Collisions

Type

Momentum Conserved?

KE Conserved?

Coefficient of Restitution (e)

Perfectly Elastic

Yes

Yes

e = 1

Inelastic

Yes

No (KE lost as heat/sound)

0 < e < 1

Perfectly Inelastic

Yes

Maximum loss

e = 0

Coefficient of Restitution (e)

e = (Relative velocity of separation) / (Relative velocity of approach)

e = (v₂ – v₁) / (u₁ – u₂)

For elastic collision: e = 1; for perfectly inelastic: e = 0.

Head-On Elastic Collision — Final Velocities

For two masses m₁ and m₂ with initial velocities u₁ and u₂:

v₁ = [(m₁ – m₂)u₁ + 2m₂u₂] / (m₁ + m₂)

v₂ = [(m₂ – m₁)u₂ + 2m₁u₁] / (m₁ + m₂)

Special Cases of Elastic Collision

Condition

Result

m₁ = m₂ (equal masses)

Velocities exchange: v₁ = u₂, v₂ = u₁

m₁ >> m₂ (massive hitting light, u₂ = 0)

v₁ ≈ u₁, v₂ ≈ 2u₁ (light body bounces at ≈ 2u₁)

m₂ >> m₁ (light hitting massive, u₂ = 0)

v₁ ≈ –u₁ (reverses), v₂ ≈ 0

Perfectly Inelastic Collision

Both objects stick together after collision:

m₁u₁ + m₂u₂ = (m₁ + m₂)v_common

v_common = (m₁u₁ + m₂u₂) / (m₁ + m₂)

KE lost = ½m₁u₁² + ½m₂u₂² – ½(m₁+m₂)v²


Most Important Formulas — Quick Reference

Work

Formula

Use

W = Fs cosθ

Constant force at angle θ to displacement

W = ∫F·dx

Variable force

W = area under F–x graph

Graphical problems

W_gravity = mgh (down)

Object falls height h

W_spring = ½kx²

Spring compressed/stretched by x

Energy

Formula

Use

KE = ½mv²

From speed

KE = p²/(2m)

From momentum

PE_gravity = mgh

Height above reference

PE_spring = ½kx²

Spring compression/extension

W_net = ΔKE

Work-energy theorem

KE + PE = constant

Conservation (no friction)

F = –dU/dx

Force from PE function

Power

Formula

Use

P = W/t

Average power

P = Fv cosθ

Instantaneous power

P = Fv

Maximum (F ∥ v)

η = P_out/P_in × 100%

Efficiency

Collisions

Formula

Use

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Conservation of momentum

e = (v₂–v₁)/(u₁–u₂)

Coefficient of restitution

v_common = (m₁u₁+m₂u₂)/(m₁+m₂)

Perfectly inelastic

Most Asked Topics — JEE Main & NEET

JEE Main (2018–2024)

Topic

Frequency

Question Type

Work-energy theorem (with friction)

Very High

MCQ — find speed or stopping distance

Spring PE and energy conservation

High

MCQ — max compression, speed at natural length

Power = Fv problems

High

MCQ — instantaneous or average power

Elastic collision — final velocities

High

MCQ — speed after collision

KE–momentum relation

Medium

MCQ — comparison problems

Conservative vs non-conservative forces

Medium

MCQ — conceptual

NEET (2018–2024)

Topic

Frequency

Question Type

Work done formula (angle problems)

Very High

MCQ — calculate W given F, s, θ

Conservation of mechanical energy

High

MCQ — height to speed conversion

Power = W/t and P = Fv

High

MCQ — calculate power

Perfectly inelastic collision

High

MCQ — common velocity after collision

KE and PE interconversion

Medium

MCQ — at what height is KE = PE?

To master Work, Energy and Power at the JEE Advanced level, it is important to practice challenging problems beyond theory. After studying these notes, solve the relevant questions from our Irodov Questions in JEE Syllabus collection to strengthen your concepts and develop advanced problem-solving skills.

Although work is a scalar, many mechanics setups still depend on choosing directions and components correctly; revise vector fundamentals for 2D motion if that step is unclear.

Frequently Asked Questions

What is the work-energy theorem in Class 11 Physics?

The work-energy theorem states that the net work done on an object by all forces acting on it equals the change in its kinetic energy: W_net = ΔKE = ½mv² – ½mu². It applies whether the forces are constant or variable and is derived directly from Newton's second law combined with kinematics. It is one of the most powerful tools in mechanics for finding speeds without knowing acceleration at every instant.

What are the most important formulas in work energy and power for JEE?

The highest-priority formulas are: W = Fs cosθ (work by constant force), W_net = ΔKE (work-energy theorem), KE = ½mv² = p²/(2m), PE_spring = ½kx², PE_gravity = mgh, mechanical energy conservation (KE + PE = constant), P = Fv (instantaneous power), and collision formulas (e = relative velocity ratio; common velocity for perfectly inelastic). These cover over 85% of all JEE Main and NEET questions from this chapter.

What is the weightage of work energy and power in JEE Main?

Work, Energy and Power carries approximately 4–6% weightage in JEE Main Physics, contributing 2–3 questions (8–12 marks) per year. Based on JEE Main papers from 2018 to 2024, work-energy theorem applications, spring energy conservation, and power (P = Fv) problems are the most consistently tested topics. The chapter is foundational — its concepts also appear embedded in rotational dynamics and collision problems.

What is the difference between elastic and inelastic collision?

In an elastic collision, both momentum and kinetic energy are conserved (coefficient of restitution e = 1). In an inelastic collision, momentum is conserved but kinetic energy is lost as heat or sound (0 < e < 1). In a perfectly inelastic collision, the objects stick together after impact, momentum is conserved, and kinetic energy loss is maximum (e = 0). All real-world collisions are inelastic to some degree.

When is work done by a force equal to zero?

Work done by a force is zero when: (1) the force is perpendicular to the displacement (θ = 90°) — for example, the normal force on a horizontal surface, or centripetal force in circular motion, (2) there is no displacement (the object does not move), or (3) the force is zero. The formula W = Fs cosθ confirms all three cases: cosθ = 0 for perpendicular force, and either F or s = 0 for the other cases.

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