Carbonyl Compound - JEE Advanced Previous Year Questions with Solutions

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Simulator   Previous Years JEE Advance Questions Paragraph for Question Nos. 1 to 3 A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S. [esquestion] The structure of the carbonyl compound P is #tag# [IIT 2009] #sol# (B) [/esquestion] [esquestion] The structure of the products Q and R, respectively, are #tag# [IIT 2009] #sol# (A) [/esquestion] [esquestion] The structure of the product S is #tag# [IIT 2009] #sol# (B) [/esquestion] Paragraph for Questions Nos. 4 to 5 An acyclic hydrocarbon P, having molecular formula $\mathrm{C}_{6} \mathrm{H}_{10}$, gave acetone as the only organic product through the following sequence of reactions, in the which Q is an intermediate organic compound. [esquestion] The structure of compound P is - #tag# [IIT 2011] #sol# (D) [/esquestion] [esquestion] The structure of the compound Q is – #tag# [IIT 2011] #sol# (B) [/esquestion] [esquestion] The number of aldol reaction(s) that occurs in the given transformation is #tag# [IIT 2012] #sol# (C) [/esquestion] [esquestion] Among P, Q, R and S, the aromatic compound(s) is / are : #tag# [IIT 2013] #sol# (A,B,C,D) [/esquestion] [esquestion] After completion of the reactions (I and II), the organic compound(s) in the reaction mixtures is(are) (A) Reaction I : P and Reaction II : P (B) Reaction I : U, acetone and Reaction II : Q acetone (C) Reaction I : T, U, acetone and Reaction II : P (D) Reaction I : R, acetone and Reaction II : S acetone #tag# [IIT 2013] #sol# (C) In basic medium halogenation dose not stop with replacement of just one hydrogen and poly halogenation takes place because -haloketones are more reactive towards base and haloform reaction takes place In above reaction $\mathrm{Br}_{2}$ is limiting agents. [/esquestion] [esquestion] The major product in the following reaction is #tag# [IIT 2014] #sol# (D) (i) Grignard prefer to give nucleophilic addition on polar $\pi$-bond and form anion intermediate. (ii) In next step anion give intramolecular nucleophilic substitution reaction & form 5 membered ring. [/esquestion] [esquestion] The major product of the following reaction is – #tag# [IIT 2015] #sol# (A) Mechanism : [/esquestion] [esquestion] In the following reactions, the product S is – #tag# [IIT 2015] #sol# (A) [/esquestion] [esquestion] The reaction(s) leading to the formation of 1,3,5-trimethylbenzene is (are) #tag# [JEE Adv. 2018] #sol# (A,B,D) [/esquestion] [esquestion] In the following reaction sequence, the amount of D (in g) formed from 10 moles of acetophenone is____. (Atomic weight in g mol–1: H = 1, C = 12, N = 14, O = 16, Br = 80. The yield (%) corresponding to the product in each step is given in the parenthesis) #tag# [JEE Adv. 2018] #sol# 495 [/esquestion]

Once Carbonyl Compounds - JEE Advanced PYQs (Chemistry) is complete, practise the topic within real timed papers from the JEE Advanced exam paper.