Solid State - JEE Advanced Previous Year Questions with Solutions
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Simulator Previous Years JEE Advance Questions [esquestion] The correct statement(s) regarding defects in solid is (are) (A) Frenkel defect is usually favoured by a very small difference in the sizes of cation and anion. (B) Frenkel defect is a dislocation defect (C) Trapping of an electron in the lattice leads to the formation of F‑center. (D) Schottky defects have no effect on the physical properties of solids. #tag# [JEE 2009] #sol# (B,C) [/esquestion] [esquestion] The packing effeciency of the two-dimensional square unit cell shown below is (A) 39.27% (B) 68.02% (C) 74.05% (D) 78.54% #tag# [JEE-2010] #sol# (D) [/esquestion] [esquestion] The number of hexagonal faces that present in a truncated octahedron is. #tag# [JEE-2011] #sol# 8 [/esquestion] [esquestion] A compound $\mathrm{M}_{\mathrm{p}} \mathrm{X}_{\mathrm{q}}$ has cubic close packing (ccp) arrangement of X. Its unit cell structure is shown below. The empirical formula of the compound is : (A) MX (B) $\mathrm{MX}_{2}$ (C) $\mathrm{M}_{2} \mathrm{X}$ (D) $\mathrm{M}_{5} \mathrm{X}_{14}$ #tag# [JEE-2012] #sol# (B) [/esquestion] [esquestion] The arrangement of $\mathrm{X}^{-}$ ions around $\mathrm{A}^{+}$ ion in solid AX is given in the figure (not drawn to scale). If the radius of $\mathrm{X}^{-}$ is 250 pm, the radius of $\mathrm{A}^{+}$ is - (A) 104 pm (B) 125 pm (C) 183 pm (D) 57 pm #tag# [JEE-2013] #sol# (A) [/esquestion] [esquestion] The correct statement(s) for cubic close packed (ccp) three dimensional structure is (are) (A) The number of the nearest neighbours of an atom present in the topmost layer is 12 (B) The efficiency of atom packing is 74% (C) The number of octahedral and tetrahedral voids per atom are 1 and 2, respectively (D) The unit cell edge length is $2 \sqrt{2}$ times the radius of the atom #tag# [JEE - Adv. 2016] #sol# (B,C,D) CCP is ABC ABC ..... type packing (A) In topmost layer, each atom is in contact with 6 atoms in same layer and 3 atoms below this layer. [/esquestion] [esquestion] A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g $\mathrm{cm}^{-3}$, then the number of atoms present in 256g of the crystal is $\mathrm{N} \times 10^{24}$. The value of N is #tag# [JEE - Adv. 2017] #sol# 2 [/esquestion] [esquestion] Consider an ionic solid MX with NaCl structure. Construct a new structure (Z) whose unit cell is constructed from the unit cell of MX following the sequential instructions given below. Neglect the charge balance. (i) Remove all the anions (X) except the central one (ii) Replace all the face centered cations (M) by anions (X) (iii) Remove all the corner cations (M) (iv) Replace the central anion (X) with cation (M) #tag# [JEE - Adv. 2017] #sol# 3 [/esquestion]
After solving Solid State - JEE Advanced PYQs (Chemistry), explore the complete papers to understand the broader question mix through the JEE Advanced PYQ.
Frequently Asked Questions
What is the weightage of Solid State in JEE Advanced?
Solid State typically contributes 1–2 questions per year in JEE Advanced, worth 4–8 marks. While that may seem small, these questions are highly predictable in topic (defects, packing, unit cell density) and often appear as high-scoring integer or multi-correct types where thorough preparation almost guarantees full marks.
Which Solid State topics are most repeated in JEE Advanced?
Crystal defects (especially Frenkel vs. Schottky distinctions and F-centres), packing efficiency of 2D and 3D unit cells, CCP structure properties, and density calculations for FCC unit cells are the most frequently tested topics. Together they account for roughly 80% of all Solid State questions asked between 2009 and 2023.
Is NCERT enough for Solid State in JEE Advanced?
NCERT Class 12 Chemistry Chapter 1 is the necessary foundation, but it is not sufficient on its own for JEE Advanced. NCERT covers definitions and basic formulas. JEE Advanced questions require you to apply those concepts in multi-step problems — for example, transforming an NaCl unit cell through four operations and counting atoms at each stage, as seen in the 2017 paper.
How do you calculate packing efficiency for a 2D square unit cell?
For a 2D square unit cell where atoms touch along the edge (edge length a = 2r): calculate the area of atoms inside the cell divided by the total area of the cell. For the arrangement in JEE 2010, this gives 2πr² / 4r² × 100 = 78.54%. Always identify how many atoms belong to the cell before applying the formula.
How many nearest neighbours does an atom have in the topmost layer of a CCP structure?
An atom in the topmost layer of a CCP structure has 9 nearest neighbours: 6 in the same layer and 3 in the layer directly below it. This is different from an atom in an interior (bulk) layer, which has 12 nearest neighbours. JEE Advanced 2016 specifically tested this distinction in its multi-correct question.